Cyclohexanol To Cyclohexene Balanced Equation

On Percent Yields

Dehydration of Cyclohexanol to Cyclohexene.

Theoretical yield. Showtime write out the counterbalanced equation. This is a very simple case. I reactant

produces one product (water is also a product but nosotros are only interested in the cyclohexene here) in a

1:1 ratio. Note that the phosphoric acid is a catalyst and is non involved in the yield calculation.

OH (H + )

(heat)

+HOH

i mol one mol

One molecule of cyclohexanol should produce one molecule of cyclohexene. One mole (mol) of

cyclohexanol should produce one mole of cyclohexene.

If 2.05 thousand of cyclohexanol is used (use the actual corporeality used in your experiment) catechumen this to

moles past dividing past the molecular weight of cyclohexanol (MW = 100.ii chiliad/mol).

two.05 one thousand cyclohexanol / 100.2 chiliad/mol = 0.0205 mol (or 20.5 mmol)

Because i mol of cyclohexanol should produce ane mol of cyclohexene, 0.0205 mol of cyclohexanol

should produce 0.0205 mol of cyclohexene. Convert this number of moles of cyclohexene to grams of

cyclohexene by multiplying by the MW of cyclohexene (82.ane g/mol).

0.0205 mol 10 82.one g/mol = one.68 g cyclohexene

In other words, two.05 g of cyclohexanol should produce ane.68 k of cyclohexene. This is the best-case

yield also known every bit the theoretical yield.

Percent Yield. The theoretical yield is what would be obtained in an platonic world, if every molecule of

cyclohexanol were converted to a molecule of cyclohexene. The percent yield is the percentage of the

theoretical yield that you really obtain later on isolating production at the end of the procedure.

Let'south say that afterwards the final fractional distillation of the cyclohexene, one.22 g was collected. The

percent yield then would be

per centum yield = (bodily / theoretical) x 100 = (1.22 yard / 1.68 thou) 10 100 = 73 %

This assumes that the i.22 g that was obtained was 100% pure. Permit's say that when the gas

chromatographic analysis was done the sample was found to be 89% cyclohexene and xi% toluene.

This means that the 1.22 g of liquid isolated in the distillation was not pure cyclohexene. The actual

corporeality of cyclohexene collected and then was 1.22 g x 0.89 = 1.09 k (pocket-size print: an assumption is being

made: that the gc detector response is the same for cyclohexene and toluene. We will take this assumption for

our purposes. In fact it is a adept supposition in this instance).

The percent yield then would be (1.09 g actual / 1.68 g theoretical) x 100 = 65%.

Cyclohexanol To Cyclohexene Balanced Equation,

Source: https://www.studocu.com/en-ca/document/university-of-alberta/cyclohexanol-to-cyclohexane-calculations/yield-calculations/3396638